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LT1934IS6 Ver la hoja de datos (PDF) - Linear Technology

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LT1934IS6 Datasheet PDF : 20 Pages
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LT1934/LT1934-1
APPLICATIONS INFORMATION
Table 2. Inductor Vendors
VENDOR PHONE
Murata
(404) 426-1300
Sumida
(847) 956-0666
Coilcraft (847) 639-6400
Würth
(866) 362-6673
Electronics
URL
www.murata.com
www.sumida.com
www.coilcraft.com
www.we-online.com
PART SERIES
LQH3C
CR43
CDRH4D28
CDRH5D28
DO1607C
DO1608C
DT1608C
WE-PD1, 2, 3, 4
COMMENTS
Small, Low Cost, 2mm Height
the average inductor current equals the load current, the
maximum load current is:
IOUT(MAX) = IPK – ΔIL/2
where IPK is the peak inductor current and ΔIL is the
peak-to-peak ripple current in the inductor. The ripple
current is determined by the off time, tOFF = 1.8μs, and
the inductor value:
ΔIL = (VOUT + VD) • tOFF/L
IPK is nominally equal to ILIM. However, there is a slight
delay in the control circuitry that results in a higher peak
current and a more accurate value is:
IPK = ILIM + 150ns • (VIN – VOUT)/L
These expressions are combined to give the maximum
load current that the LT1934 will deliver:
IOUT(MAX) = 350mA + 150ns • (VIN – VOUT)/L – 1.8μs
• (VOUT + VD)/2L (LT1934)
IOUT(MAX) = 90mA + 150ns • (VIN – VOUT)/L – 1.8μs
• (VOUT + VD)/2L (LT1934-1)
The minimum current limit is used here to be conservative.
The third term is generally larger than the second term,
so that increasing the inductor value results in a higher
output current. This equation can be used to evaluate
a chosen inductor or it can be used to choose L for a
given maximum load current. The simple, single equation
rule given above for choosing L was found by setting
ΔIL = ILIM/2.5. This results in IOUT(MAX) ~0.8ILIM (ignoring
the delay term). Note that this analysis assumes that the
inductor current is continuous, which is true if the ripple
current is less than the peak current or ΔIL < IPK.
The inductor must carry the peak current without satu-
rating excessively. When an inductor carries too much
current, its core material can no longer generate ad-
ditional magnetic flux (it saturates) and the inductance
drops, sometimes very rapidly with increasing current.
This condition allows the inductor current to increase
at a very high rate, leading to high ripple current and
decreased overload protection.
Inductor vendors provide current ratings for power induc-
tors. These are based on either the saturation current or
on the RMS current that the inductor can carry without
dissipating too much power. In some cases it is not clear
which of these two determine the current rating. Some data
sheets are more thorough and show two current ratings,
one for saturation and one for dissipation. For LT1934 ap-
plications, the RMS current rating should be higher than
the load current, while the saturation current should be
higher than the peak inductor current calculated above.
Input Capacitor
Step-down regulators draw current from the input sup-
ply in pulses with very fast rise and fall times. The input
capacitor is required to reduce the resulting voltage ripple
at the LT1934 and to force this switching current into
a tight local loop, minimizing EMI. The input capacitor
must have low impedance at the switching frequency to
do this effectively. A 2.2μF ceramic capacitor (1μF for the
LT1934-1) satisfies these requirements.
If the input source impedance is high, a larger value ca-
pacitor may be required to keep input ripple low. In this
case, an electrolytic of 10μF or more in parallel with a 1μF
ceramic is a good combination. Be aware that the input
1934fe
9

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