HA13408
tsus = 0.118 ms
Where VCE(sat) = 1.3 V typ and VCE(sus) = 52 V typ.
Power Dissipation
Power dissipation driving an inductive load for an HA13408 is determined as follows:
First, average power dissipation (Pon) per channel at ton is obtained as follows:
Pon =.. VCE(sat) IP
VCC2 – 1
R • IP ton
L
R
(3)
Average power dissipation (Psus) at tsus:
Psus =.. VCE(sus) IP
1
tsus
L
R
–
VCE(sus) – VCC2
R • IP
(4)
Where IP and tsus are obtained in equations (1) and (2).
Average power dissipation (PT) per channel for a period is obtained as follows:
PT =..
1
T
(Pon • ton + Psus • tsus)
(5)
Where drive period is defined as T.
Power dissipation (PT) for 9 channels driven at the same time:
PT =..
9
T
(Pon • ton + Psus • tsus)
(6)
4