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ADE7762 Ver la hoja de datos (PDF) - Analog Devices

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ADE7762 Datasheet PDF : 28 Pages
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ADE7762
This is the correct active power calculation.
INSTANTANEOUS
POWER SIGNAL
INSTANTANEOUS
ACTIVE POWER SIGNAL
V× I
2
0V
CURRENT
VOLTAGE
INSTANTANEOUS
POWER SIGNAL
INSTANTANEOUS
ACTIVE POWER SIGNAL
2
I
×
cos(60°)
0V
VOLTAGE
CURRENT
60°
Figure 17. DC Component of Instantaneous Power Signal
NONSINUSOIDAL VOLTAGE AND CURRENT
The active power calculation method also holds true for non-
sinusoidal current and voltage waveforms. All voltage and
current waveforms in practical applications have some
harmonic content. Using the Fourier Transform, instantaneous
voltage and current waveforms can be expressed in terms of
their harmonic content
v(t ) = Vo + 2 × Vn × sin (nωt + αn )
(2)
n=0
where:
v(t) is the instantaneous voltage.
VO is the average value.
Vn is the rms value of voltage harmonic n.
and α n is the phase angle of the voltage harmonic.
Preliminary Technical Data
( ) i(t ) = IO + 2 × VnI × sin nωt βn
(3)
n=0
where:
i(t) is the instantaneous current.
IO is the dc component.
In is the rms value of current harmonic n.
βn is the phase angle of the current harmonic.
Using Equations 2 and 3, the active power, P, can be expressed
in terms of its fundamental active power (P1) and harmonic
active power (PH).
P = P1 + PH
where:
P1 = V 1 × I1 cos φ1
(4)
φ1 = α1 β1
PH = Vn × In cos φn
n=1
(5)
φn = αn − βn
As can be seen from Equation 5, a harmonic active power
component is generated for every harmonic, provided that
harmonic is present in both the voltage and current waveforms.
The power factor calculation has been shown to be accurate in
the case of a pure sinusoid. Therefore, the harmonic active
power also correctly accounts for power factor since harmonics
are made up of a series of pure sinusoids. A limiting factor on
harmonic measurement is the bandwidth. On the ADE7762, the
bandwidth of the active power measurement is 14 kHz with a
master clock frequency of 10 MHz.
Rev. PrB | Page 14 of 28

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